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ZJ ,$D 0 Y 25.0 g N24 (% %% 8  fdg1?@V`@00 6NEXT 8  fdg1?@j `@00 ABACK TO PROBLEMl 8 C tP   ^B  8@ 6DԔIJ 8  8 c $ԥ 7h ,$D 0 1 mol N2 28.02 g N2^ ( (2(% % % %  8 c $  s ,$  0 y= 40.0 L NH3J 1111Z  8 0 h ?,$D0 0N2 + 3H2 NH3 z8n& && &&&&&^B  8@ 6DԔM M T 8 c $ h # ,$D 0 2 mol NH3 1 mol N2j ((2(% %% %%,^B 8 6DԔ D 8 c $Th m ,$D  0 22.4 L NH3 1 mol NH3j ((2( % % % %%  8 c $Th @ ,$ 0 @25.0 g( 8 c $h @p,$ 0 =? L(^z X [ ( 8 ( ,$D 0fB 8B 6DԔX fB 8B 6DԔ3 [ (^z  s 7 8   ,$D  0fB 8B 6DԔ s & fB 8B 6DԔ 7^z X $ 8  ,$D 0fB 8B 6DԔX  fB 8B 6DԔ $^B 8 6DԔ  H 8 0޽h ? f33  <<(  <r < S g (  <  fDg1?0 ` P @00 8ANSWERl < C gP  ( H < 0޽h ? f33C  p( X   x  c $] 0      f4]1?@V`@00 = CONTINUE...    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JohannessonasRC:\Program Files\Microsoft Office\Templates\Presentation Designs\Contemporary.potrMrs. JohannessonMic23.Microsoft PowerPointoso@ @ܐ@ N/kGx#oM   & &&#TNPP0v & TNPP &&TNPP    f- "-- !-- "-& 3--- !"pH---3--- !PxH-----e ]----,e%]----De<]----tem]----e]----e]----e]----e]----e]--&------%----d]------------%----e]------&--\eU]--&M&K<--$j-;0824517.;(>&@"A?>><<< < <<=>AABBBA@@BIJJJIECA@=;865433/023320/-----//////0122233567888998888887555)  !+$3-;--&&?M-- $~|yxusrrrronmkjjiigfdcbb^^`bdffggggffedcbbcccbccfjjkklloprsuwxyyzzz{||}}~~}}}{ywusrqpqqqrsttuttjjjjjiige_^^^^^^^^\ZYXXXWUSQPOMKIGEC@?CCDEFGHIJKKKKJLLJIHHJKNPRTUWXYZ[^`bdeeffikmoq rtwy|!%'),-|.y/w0t1r2p3m5k7i8f9c:`;]<Z=X>W@TCQENGJHNIQJTKWKZK]K`LdLiLoKtKzIHFDB?=:73/,'%#  --&&Xd--,$_bccbb`^]]ZYYXXXZ\]_--&&&&G& - &Gy& --iH-- Times New Roman- .%2 BYIdeal Gas Law & Gas *$*-*. .2 Bd Stoichiometry -.--Q-- Times New Roman- .F2 *1) Work out each problem on scratch paper. #            . .2  2) Click    .BDomCasual BT- .2 eANSWER.Times New Roman- .(2  to check your answer.     . .2 4 3) Click    .BDomCasual BT- . 2 4eNEXT.Times New Roman- .42 4 to go on to the next problem.          .- 3"-0-- Times New Roman- .2 lPV =   . . 2 lnRT.- 3"-Q-- Times New Roman- .2 R = 0.0821 L.Symbol- . 2 }.Times New Roman- . 2 atm . . 2 / . . 2 mol .Symbol- . 2 .Times New Roman- .2  K = 8.315 dm.Times New Roman- . 2 3 .Symbol- . 2 .Times New Roman- . 2 kPa. . 2 / . . 2 mol.Symbol- . 2 &.Times New Roman- . 2 .K.&\lM--- !0p`----2- $`pcsEsHp---f- $`p`ccs---{{- $`HEc---\\- $HHpEsE-- "-- $`p`HHp $cscEEs%`pcs%`c%HE%HpEs--& BDomCasual BT- .2 |CLICK TO START    .--"System-&TNPP & / 0|DTimes New RomanbbDb0hbhb0DArialNew RomanbbDb0hbhb0" DDomCasual BTanbbDb0hbhb0B0DSymbolal BTanbbDb0hbhb0@DArial NarrowanbbDb0hbhb0"  @n?" dd@  @@`` ,$x.+"        C x1?@8 g4IdIdtb0lb ppp@ <4BdBd-kbF<4!d!d-kbF? %{!Ideal Gas Law & Gas Stoichiometry |1) Work out each problem on scratch paper. 2) Click ANSWER to check your answer. 3) Click NEXT to go on to the next problem.B}4  QUESTION #1How many grams of CO2 are produced from 75 L of CO at 35C and 96.2 kPa? 2CO + O2 2CO2fI( (;( ((((C ANSWER #1Find the new molar volume: n = 1 mol V = ? P = 96.2 kPa T = 35C = 308 K R = 8.315 dm3kPa/molKLaU B  ($"ANSWER #1 (con t)   QUESTION #2KHow many moles of oxygen will occupy a volume of 2.5 L at 1.2 atm and 25C?LL(>   ANSWER #2n = ? V = 2.5 L P = 1.2 atm T = 25C = 298 K R = 0.0821 Latm/molK@D9.   QUESTION #3IWhat volume will 56.0 grams of nitrogen (N2) occupy at 96.0 kPa and 21C?*J*( ((<   ANSWER #3V = ? n = 56.0 g = 2.00 mol P = 96.0 kPa T = 21C = 294 K R = 8.315 dm3kPa/molKXSG  @    QUESTION #4What  !"#$%&'()*+,(_ ^Mrs. Johannesson ՜.+,D՜.+,l(    On-screen Show -s-^  Times New RomanArial DomCasual BTSymbol Arial NarrowContemporary.pot"Idea  / 0|DTimes New RomanbbDb0hbhb0DArialNew RomanbbDb0hbhb0" DDomCasual BTanbbDb0hbhb0B0DSymbolal BTanbbDb0hbhb0@DArial NarrowanbbDb0hbhb0"  @n?" dd@  @@`` ,$x.+!        C x1?@8 g4IdIdtb0lb ppp@ <4BdBd-kbF<4!d!d-kbF? %{!Ideal Gas Law & Gas Stoichiometry |1) Work out each problem on scratch paper. 2) Click ANSWER to check your answer. 3) Click NEXT to go on to the next problem.B}4  QUESTION #1How many grams of CO2 are produced from 75 L of CO at 35C and 96.2 kPa? 2CO + O2 2CO2fI( (;( ((((C ANSWER #1Find the new molar volume: n = 1 mol V = ? P = 96.2 kPa T = 35C = 308 K R = 8.315 dm3kPa/molKLaU B  ($"ANSWER #1 (con t)   QUESTION #2KHow many moles of oxygen will occupy a volume of 2.5 L at 1.2 atm and 25C?LL(>    !"#$%&'()*+,-./0123456789:;<=>?@ABCDEFGHIJKLMNOPQRSTUVWXYZ[\]^_`abcdefghijklmnopqrstuwxyz{|}~Root EntrydO)H0k@ Current User0SummaryInformation(v8%PowerPoint Document(-^DocumentSummaryInformation8  ANSWER #2n = ? V = 2.5 L P = 1.2 atm T = 25C = 298 K R = 0.0821 Latm/molK@D9.   QUESTION #3IWhat volume will 56.0 grams of nitrogen (N2) occupy at 96.0 kPa and 21C?*J*( ((<   ANSWER #3V = ? n = 56.0 g = 2.00 mol P = 96.0 kPa T = 21C = 294 K R = 8.315 dm3kPa/molKXSG  @    QUESTION #4What volume of NH3 at STP is produced if 25.0 g of N2 is reacted with excess H2? N2 + 3H2 2NH3Q( ("( (( (( (( ((((  ANSWER #4   QUESTION #5What volume of hydrogen is produced from 25.0 g of water at 27C and 1.16 atm? 2H2O 2H2 + O2jOQ( ((((((I)% ANSWER #5Find the new molar volume: n = 1 mol V = ? P = 1.16 atm T = 27C = 300. K R = 0.0821 Latm/molK@aVB  *&"ANSWER #5 (con t)    QUESTION #6THow many atmospheres of pressure will be exerted by 25 g of CO2 at 25C and 0.500 L?*U>( ((  ANSWER #6P = ? n = 25 g = 0.57 mol T = 25C = 298 K V = 0.500 L R = 0.0821 Latm/molK@OD.*   QUESTION #7How many grams of CaCO3 are required to produce 45.0 dm3 of CO2 at 25C and 2.3 atm? CaCO3 + 2HCl CO2 + H2O + CaCl2U!( ( ( (( (( ((((((((P# ANSWER #7Find the new molar volume: n = 1 mol V = ? P = 2.3 atm T = 25C = 298 K R = 0.0821 Latm/molK@_TB  +' ANSWER #7  QUESTION #8UFind the number of grams of CO2 that exert a pressure of 785 torr at 32.5 L and 32C.*V( (7(= ANSWER #8n = ? P = 785 torr = 1.03 atm V = 32.5 L T = 32C = 305 K R = 0.0821 Latm/molK@RG@) Pbe   P(  x  c $4W 0  j    f1?@V`@00 = CONTINUE...  /  Hgֳgֳ ?  PV = nRT V = 26.6 dm3/mold  000 0   fԢ1?@j `@00 ABACK TO PROBLEMl  C ԨP  j H  0޽h ? f33G  ( X   x  c $[ 0  f    f4[1?@V`@00 = CONTINUE...     Ht[gֳgֳ ?p  PV = nRT V = 21.2 L/molB 0 0   f[1?@j `@00 ABACK TO PROBLEMr  S Ԥ[P  f H  0޽h ? f33?  0P(  Px P c $$xh 0  f  P  fxh1?@V`@00 = CONTINUE...    P Hdzhgֳgֳ ?p  PV = nRT V = 11 L/molB  0 0 P  fyh1?@j `@00 ABACK TO PROBLEMl P C DyhP  f H P 0޽h ? f33r  |)- +b(     4 = F O Y c  l Gas Law & Gas Stoichiometry QUESTION #1 ANSWER #1ANSWER #1 (con’t) QUESTION #2 ANSWER #2 QUESTION #3 ANSWER #3 QUESTION #4 ANSWER #4 QUESTION #5 ANSWER #5ANSWER #5 (con’t) QUESTION #6 ANSWER #6 QUESTION #7 ANSWER #7 ANSWER #7 QUESTION #8 ANSWER #8  Fonts UsedDesign Template Slide Titles(RZ _PID_GUID _PID_HLINKSAN{F75E5722-D6D9-11D5-91D6-00A02456D54D}A6L257,2,PV = nRT P1V1T2 = P2V2T1 R = 0.0821 Latm/molK = 8.315 dm3kPa/molKL259,4,PV = nRT P1V1T2 = P2V2T1 R = 0.0821 Latm/molK = 8.315 dm3kPa/molKL261,6,PV = nRT P1V1T2 = P2V2T1 R = 0.0821 Latm/molK = 8.315 dm3kPa/molKL263,8,PV = nRT P1V1T2 = P2V2T1 R = 0.0821 Latm/molK = 8.315 dm3kPa/molKM265,10,PV = nRT P1V1T2 = P2V2T1 R = 0.0821 Latm/molK = 8.315 dm3kPa/molKM267,12,PV = nRT P1V1T2 = P2V2T1 R = 0.0821 Latm/molK = 8.315 dm3kPa/molKM269,14,PV = nRT P1V1T2 = P2V2T1 R = 0.0821 Latm/molK = 8.315 dm3kPa/molKM276,20,PV = nRT P1V1T2 = P2V2T1 R = 0.0821 Latm/molK = 8.315 dm3kPa/molK274,16,QUESTION #8 volume of NH3 at STP is produced if 25.0 g of N2 is reacted with excess H2? N2 + 3H2 2NH3Q( ("( (( (( (( ((((  ANSWER #4   QUESTION #5What volume of hydrogen is produced from 25.0 g of water at 27C and 1.16 atm? 2H2O 2H2 + O2jOQ( ((((((I)% ANSWER #5Find the new molar volume: n = 1 mol V = ? P = 1.16 atm T = 27C = 300. K R = 0.0821 Latm/molK@aVB  *&"ANSWER #5 (con t)    QUESTION #6THow many atmospheres of pressure will be exerted by 25 g of CO2 at 25C and 0.500 L?*U>( ((  ANSWER #6P = ? n = 25 g = 0.57 mol T = 25C = 298 K V = 0.500 L R = 0.0821 Latm/molK@OD.*   QUESTION #7How many grams of CaCO3 are required to produce 45.0 dm3 of CO2 at 25C and 2.3 atm? CaCO3 + 2HCl CO2 + H2O + CaCl2U!( ( ( (( (( ((((((((P# ANSWER #7Find the new molar volume: n = 1 mol V = ? P = 2.3 atm T = 25C = 298 K R = 0.0821 Latm/molK@_TB  +' ANSWER #7  QUESTION #8UFind the number of grams of CO2 that exert a pressure of 785 torr at 32.5 L and 32C.*V( (7(= ANSWER #8n = ? P = 785 torr = 1.03 atm V = 32.5 L T = 32C = 305 K R = 0.0821 Latm/molK@RG@) Pb,#   ""0!! 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